Question

Solve each system of linear equations by elimination.
3a - 2b + 4 = 0
2a - 5b - 1 = 0

Answer 1

You have to multiply one equation or both to make something cancel out

Answer 2

What do i multiply by

Answer 3

I would start with multiplying the second equation by -3

Answer 4

3a - 2b + 4 = 0
2a - 5b - 1 = 0

Answer 5

move -1 and 4 on right side

Answer 6

3a - 2b =-4
2a - 5b =1

Answer 7

subctarct equation 2 from euqation 1. this will help
3a-2b-2a+5b=-5

Answer 8

a+3b=-5

Answer 9

a=-5-3b

Answer 10

now substitue a into one of the eqautions and solve for b

Answer 11

3( -5-3b)- 2b =-4

Answer 12

-15-9b-2b=-4

Answer 13

-11b=11

Answer 14

b=-11/11=????????????
after finding b substute b into one of the original eqautions and solve for a

Answer 15

@shelby1290 tell me what are the values of b and a use my instructions

Answer 16

@AlexandervonHumboldt2 don't I have to multiply the second equation by -3 first. You know, like what jess said earlier

Answer 17

ok

Answer 18

She has to solve it by elimination.

Answer 19

No, you were trying to do substitution.

Answer 20

ahhh well

Answer 21

Yea, i need to solve it by elimination^

Answer 22

you are both wrong

Answer 23

eliminationDemonstrates how to solve a linear system using the technique of addition and subtracting i gogloed it

Answer 24

hmm

Answer 25

Yes, and you were doing substitution...

Answer 26

I'm so confused right now....

Answer 27

@shelby1290 , fan me please

Answer 28

I need to eliminate the systems. Just eliminate.

Answer 29

brb fan me too then

Answer 30

so ok

Answer 31

lets do elimination method