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Algebra 19 Online
OpenStudy (anonymous):

$5400  is invested, part of it at  11%  and part of it at  6%.  For a certain year, the total yield is  $ 474.00.   How much was invested at each rate?

OpenStudy (anonymous):

@kohai

OpenStudy (kohai):

I was never good with this, sorry :(

OpenStudy (anonymous):

k

OpenStudy (anonymous):

what about the substitution method @kohai

OpenStudy (anonymous):

(5400-x)*(1+.011)+x(1+0.06) is what you are looking for! Where x is amount invested at 6%

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