Question

What are the values of x and y?

Answer 1

I saw this question earlier from another user.... Still trying to figure out how 12 is greater than 16... but anyhow, @Kainui may be able to help you.

Answer 2

now you can see that BC is x DC is 16 AC is 12+16 = 28, so taking the last two ratios we get x^2 = 28*16 so x=\[8\sqrt{7}\]

Answer 3

Refer to the attachment from the Mathematica 9 program.