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\[\int\limits_{}^{} dy/ (7-2y)\]
I tried separating the fraction... I'm not sure why it doesn't work like that
\(u=7-2y\) you will get a log
oh dear you cannot separate fractions like that
ooohhh lol I said 1/(7-2y) = 1/7 - 1/2y. Man I feel dumb xD
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\[\frac{1}{3+5}\neq \frac{1}{3}+\frac{1}{5}\]
Alrighty, I got it from here thank you :)
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