Question

I shoot something vertically. The speed was 25m/s when the object was at 1/4 of the max height. Which was the initial speed?

Answer 1

Let the maximum height is h

Answer 2

So u will get 2 equations
25^2=u^2-2*9.8*h/4
And 0^2=u^2-2*9.8*h

Answer 3

Frm above 2 equations find
u=?

Answer 4

I used equation v^2=u^2-2*g*h