Question

find the 9th term of the sequence described by :
A(n)=7+(n-1)(3)

A.42

B.9

C.31

D.27

Answer 1

@inowalst @QemarGray6 @Love_Ranaa @Conqueror @Abhisar

Answer 2

\(\large\color{black}{ \displaystyle a_{n}=7+3(n-1) }\)
is the formula for any \(\large\color{black}{ \displaystyle n }\)th term in the sequence.

For instance, if I wanted to find the 5th term, I would do the following.
\(\large\color{black}{ \displaystyle a_{5}=7+3(5-1)=7+3(2)=7+6=13 }\)
So, \(\large\color{black}{ \displaystyle a_{5}=13 }\)

Answer 3

so would it be B ?? @SolomonZelman

Answer 4

My formula is \(\large\color{black}{ \displaystyle a_{n}=7+3(n-1) }\).

just as I plugged in 5 for n to find the 5th term, so would I plug in 9 for n to find the 9th term.

it is not B.

Answer 5

D

Answer 6

@SolomonZelman

Answer 7

Alright, can you plug in 9 for n, into: \(\large\color{black}{ \displaystyle A_{n}= 7~+~3(n-1) }\) ??

\(\Large\color{black}{ \displaystyle A_{\color{red}{9}}= 7~+~3(\color{red}{9}-1) }\)

Answer 8

then, all you have to do is to simplify the right hand side of the question.

Answer 9

of the *equation*

Answer 10

i got A .:)

Answer 11

@SolomonZelman

Answer 12

1) what is 9-1?
2) multiply that times 3, what do you get after this?
3) Then add 7 to the number that you got from 2 previous steps.

Answer 13

31!!!!!!!!!