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MEDAL AND FAN! The table and the graph each show a different relationship between the same two variables, x and y:
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How much more would the value of y be in the table than its value on the graph when x = 11?
on the chart the last x value is 6. 6 +what =11
that =s 5
80x5
400
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add that to 480
=960
thats on the chart
on the graph the x=11 is y=540 960-540=??
420
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finnal answer !!!
for the table y = 80x so for x=11 y=880 note for the graph you get y by multiplying x by 45 - when x = 2, y =90 when x = 4 y = 180 so what would be the value of y when x = 11?
420 is incorrect
ok then whats the answer and sorry i got it wrong
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