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Use the zeros of the following quadratic to find the x-value of the vertex. 2003-18-02-00-00_files/i0170000.jpg
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y=x^2-2x+1
where the image
its that problem i just posted
oh ok... one sec
y=x^2-2x+1 y-1=x^2-2x y-1/2=x^2-x y-1/2=x^3
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those answers arent showing up
a.1 b.-1 c.-2 d.2
y=x^2-2x+1 y=1^2-2(1)+1 y=1-2+1 y=0
just solve the rest just like that
thanks!!!!!
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