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H(x)= {((sin(5pix)-1)/(2x-1)) x=not1/2, k x=1/2}
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\[h(x)=\left[\begin{matrix}\frac{ \sin(5 \pi x) - 1 }{ 2x-1 } & x \neq \frac{ 1 }{ 2 } \\ k & x \neq \frac{ 1 }{ 2 }\end{matrix}\right]\]
Find the value of k that would make the function continuous in each case.
ok that should say k , when x = 1/2
we need to find limit [sin (5pix) - 1 ] / ( 2x-1) as x->1/2
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