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OpenStudy (anonymous):
If (6^2)^x = 1, what is the value of x? Explain your answer.
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OpenStudy (darkbluechocobo):
0?
OpenStudy (alexandervonhumboldt2):
ok so 36^x=1 x=0
OpenStudy (alexandervonhumboldt2):
a^0=1
OpenStudy (darkbluechocobo):
Because if you set anything to the power of 0 it equals 1
OpenStudy (anonymous):
OH now i remember because I learned it but I forgot it thank you both so much
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OpenStudy (darkbluechocobo):
you are quite welcome
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