Question

David measured the distance from his house to a soccer field as 3 km. The actual distance from his house to the soccer field is 2.84 km.



What is the approximate percent error in David’s measurement? Round to the nearest tenth of a percent, if necessary.
I think the answer is A








A.

0.16%








B.

5.3%








C.

5.6%








D.

16%

Answer 1

((3-2.84)/3)*100=?

Answer 2

=5.333333

Answer 3

change / actual as a percentage

Answer 4

triciaal is telling you that you should divide the by the *true distance* 2.84
not by the measurement 3