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Is this correct? Discriminant and real number solutions
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x^2 + 6x - 3 = 0 a = 1, b = 6, c = -3 Formula = b^2 - 4ac 6^2 - 4 * 1 * (-3) = 36 - 4 * 1 * (-3) = 36 - 4 * (-3) = 36 - (-12) = 48 Discriminant = 48 The quadratic equation has two real number solutions because the value of the discriminant is positive.
correct
Thanks:)
Can you check 6 more?
Goodness.... 6 more x_x Just find the rules for discriminants and their solutions, haha.
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