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what are the asymptotes of f(x)=tan(2x-pi) from x=pi/2 to x=3pi/2?
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@Kainui
put Cos(2x-pi) = 0
ten calculate in the given range
then...
@Patsfan12 atleast you can ask your doubt or anything.
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Pi/2
no
\[2x-\pi = (2n+1)\pi/2, x= 3\pi/4, 5\pi/4\] in the given range.
My answer choices are: X=3pi/4,x=5pi/4 X=0x=pi, x=2pi X=0,x=pi/4 X=pi/2, x=3pi/2
So the first choice!
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yeah. and i am a decent guy you took me wrong
Right you are again
but u've blocked me.
I unblocked you
really tell me would u talk?
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lets be friends
i will try to help you the way i can.
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