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Engineering 11 Online
OpenStudy (ksaimouli):

Inertia

OpenStudy (ksaimouli):

@esamalaa problem 2

OpenStudy (ksaimouli):

That is the attachment. please download I'll delete it soon

OpenStudy (anonymous):

ok you will dived the shape into 2 parts a triangle and quarter circle, then you will fine the centroide for each

OpenStudy (ksaimouli):

its actually 2nd one

OpenStudy (ksaimouli):

My though square and subtract 4 semicircles

OpenStudy (ksaimouli):

The moment of inertia of semicircle= 4R/3pi

OpenStudy (ksaimouli):

sorry above is the centroid

OpenStudy (ksaimouli):

Moment of Inertia about the center= \[\frac{ \pi r^4 }{ 8 }- \frac{ 8r^4 }{ 9 \pi }\]

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