Question

Chapter 5:Indices and Logarithms
@mathmath333

Answer 1

\[Given~\log _{3}m=2-\log _{3}n,\]express m in terms of n.

Answer 2

\(\large \begin{align} \color{black}{\log _{3}m=2-\log _{3}n \hspace{.33em}\\~\\
\log _{3}m+\log _{3}n=2 \hspace{.33em}\\~\\
\log _{3}(m\times n)=2 \hspace{.33em}\\~\\
3^2=m\cdot n \hspace{.33em}\\~\\
m=\dfrac{9}{n} \hspace{.33em}\\~\\
}\end{align}\)

Answer 3

Beautiful :)

Answer 4

Thnx @mathmath333 :)

Answer 5

yw