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Mathematics 12 Online
OpenStudy (yamyam70):

Help in determining the variable given m , 4m - 8 , m^2 - 6 solve for the value of m

OpenStudy (ribhu):

4m-8 = 0; m^2 -6 = 0

OpenStudy (yamyam70):

so m for the 3rd term = m = sqrt6 ??

OpenStudy (ribhu):

yeah

OpenStudy (ribhu):

@yamyam70 u got it

OpenStudy (yamyam70):

so we have different values for m per given term

OpenStudy (ribhu):

yeah thats what i think.

OpenStudy (yamyam70):

thanks a lot :)

OpenStudy (ribhu):

ok no issues any more problem

OpenStudy (yamyam70):

Im good , thanks :)

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