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Mathematics 13 Online
OpenStudy (adamaero):

AFTER Cartesian vector form? Crate = 140-lb 0 = (-6/7)T_AB - (6/7)T_AC 0 = (3/7)T_AB - (2/7)T_AC 0 = (2/7)T_AB + (3/7)T_AC - 140 ?

OpenStudy (adamaero):

OpenStudy (phi):

you can put the origin anywhere you like, but A looks like a good place

OpenStudy (adamaero):

so 0 = (-6/7)T_AB - (6/7)T_AC 0 = (3/7)T_AB - (2/7)T_AC 0 = (2/7)T_AB + (3/7)T_AC - 140 (weight not described in posted pic) ?

OpenStudy (adamaero):

@satellite73 @Directrix @Loser66

OpenStudy (phi):

Your 2nd and 3rd equations are ok. but the forces in the first are balanced by AD in other words, the equation should read 0 = (-6/7)T_AB - (6/7)T_AC + T_AD you can use eq 2 and eq 3 to solve for T_AB and T_AC and then use those values in the 1st equation to find T_AD

OpenStudy (adamaero):

What? There is no T_AD with a length.

OpenStudy (phi):

T_AD is the tension in the direction A to D. all of these vectors are unit length, and then scaled by the tension.

OpenStudy (adamaero):

I thought I could ignore it

OpenStudy (phi):

AD is part of the system.

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