Please help Factor 3x2 - 12x - 36 completely.
3x^2 - 12x - 36 = 3(x^2 - 4x - 12) to factor x^2 - 4x - 12, you need to find two numbers that multiply to -12 and add to -4
So would it be 3(x+4)(x-3) ?
4 times -3 is -12 but 4 plus -3 is not -4
I'm a little confused.
which factors of -12 also add to -4 ?
oh 6 and 2?
example: -1 and 12 multiply to -12 but they don't add to -4
close
Im just confused because my options are 3(x-6)(x+2) , (3x+6)(x-2) , 3(x+4)(x-3) and (3x-4)(x+3) so I dont understand if it 3 and 4 dont work into that and 6 and 2 dont either?
well it's not 6 and -2 since 6 plus -2 = +4 it's actually -6 and 2 because -6 plus 2 = -4
so x^2 - 4x - 12 factors to (x-6)(x+2)
3x^2 - 12x - 36 = 3(x^2 - 4x - 12) 3x^2 - 12x - 36 = 3(x-6)(x+2)
Oh okay that makes more sense
could you help me with another question
sure
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