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How deep would the water be if the Earth was smooth?
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Earth water = 1,386,000,000 km^3 Earth radius = 6371 km
|dw:1424073312912:dw|
from here we can calculate R2 and hence the depth
R2 would be 6371km
well then we work out R1 using the above and hence the depth
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is volume 4/3piR^3?
\[V_W=\frac43\pi R_2^3-\frac43\pi R_1^3\]\[\frac43\pi R_2^3=\frac43\pi R_1^3+V_W\]\[R_1^3=R_2^3-\frac{3V_W}{4\pi}\]
This won't work... I'm removing the radius of the volume, not the volume.|dw:1424075128874:dw|
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