Use the function ƒ(x) = 2 - 5x to fill in the blanks in the table.
-2 ____________
-1 ____________
0 _____________
1 _______________
2 ________________
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pooja195 (pooja195):
plug in each number in place of x
pooja195 (pooja195):
5x
OpenStudy (eric_d):
Substitute the given values into the function
OpenStudy (eric_d):
@stoner_life
pooja195 (pooja195):
ƒ(x) = 2 - 5(-2)
ƒ(x) = 2 - 5(-1)
ƒ(x) = 2 - 5(0)
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OpenStudy (anonymous):
ima need more help then this!
pooja195 (pooja195):
i set it up for u lol
pooja195 (pooja195):
you just have to solve
OpenStudy (anonymous):
all it shows is a bunch of ? marks!
pooja195 (pooja195):
refresh
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pooja195 (pooja195):
ƒ(x) = 2 - 5(1)
ƒ(x) = 2 - 5(2)
pooja195 (pooja195):
lets start with the first one whats -5x-2?
OpenStudy (anonymous):
idek okay .
pooja195 (pooja195):
you need to try
pooja195 (pooja195):
whats 5x2??
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OpenStudy (anonymous):
damn ive already tryed this stuff aint easy like you think it is!
OpenStudy (anonymous):
its 10
pooja195 (pooja195):
ok good ƒ(x) = 10
pooja195 (pooja195):
thats the answer for the first one
next: 5x-1=?
pooja195 (pooja195):
5 times -1 do you know?
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pooja195 (pooja195):
ok seems your stuck whats 5 times 1?
OpenStudy (eric_d):
When x=-2, f(-2)=2-5(-2) =\(12\) rite instead of 10