Elm. Algebra question -- answer seems correct, however program is insisting it's wrong.

Question

ashleyisakitty · Answer

attachment

ashleyisakitty · Answer

|dw:1424104048924:dw|

anonymous · Answer

Could they be asking for total length and total width?

luigi0210 · Answer

Also, perimeter is 2l+2w right? Or am I that rusty on formulas? 

2*220 gives 440 which is bigger than the overall perimeter?

anonymous · Answer

Hold on..

Perimeter of a rectangle:

$P = 2(l + w)$

$P = 2(220 + 44)$

$P = 2(264)$

$P = 528$

$P \ne 264$

anonymous · Answer

$$2(l+b)=2(5b+b)=2 \times 6b=12b$$
$$12b=264$$
$$b=\frac{264}{12}=22$$
$$l=5b=5 \times 22=110$$

mimi_x3 · Answer

Yup I got the same answer as @Nishant_Garg

anonymous · Answer

Both values are doubled

luigi0210 · Answer

Yea, you forgot to account for both sides is all.

anonymous · Answer

Yep, so just divide them by 2.

22 / 2 = ?

220 / 2 = ?

anonymous · Answer

that's why I asked if they asked for total length width

anonymous · Answer

44 / 2*

ashleyisakitty · Answer

Thanks, I was following the wrong formula. Thanks everyone.

anonymous · Answer

Same, I was adding at first xD

luigi0210 · Answer

You're welcome, and gewwddd lucckk