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OpenStudy (anonymous):
Find dr/dt for r=(csc(t)+cot(t))^-1
I tried chain rule and got
-(csct+cott)^-2*-csct+cott+(-csc^2t)
Anyone see my error?
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OpenStudy (anonymous):
no
OpenStudy (kmeis002):
check the derivative of \(csc(t)\), plus be careful with your parenthesis.
OpenStudy (welshfella):
i cant remember the derivatives of cosec and cot...
OpenStudy (kmeis002):
and your addition signs, I'm not sure if you meant to put it there or if there's a typo.
OpenStudy (idku):
I would re-write in sines and cosines in the parenthesis combine and then differentiate using quotient,.
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OpenStudy (anonymous):
deriv of csc(t) is -csc(t)*cot*(t) I don't think that part is incorrect. Are my parenthesis effecting my answer?
OpenStudy (welshfella):
derivative of cscc x = -cot x csc x and of cot x is - csc^2 x
OpenStudy (kmeis002):
You have it is \(-csc(t)+cot(t)\)
OpenStudy (welshfella):
* csc x
OpenStudy (welshfella):
yes the whole of the second part should be in parentheses
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OpenStudy (anonymous):
Thank you so much! I suck at this stuff
OpenStudy (welshfella):
yw
- it needs some practice to get confident in the more complicated derivatives
OpenStudy (anonymous):
Some calculations using Mathematica 9 are attached.
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