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Mathematics 14 Online
OpenStudy (anonymous):

Find dr/dt for r=(csc(t)+cot(t))^-1 I tried chain rule and got -(csct+cott)^-2*-csct+cott+(-csc^2t) Anyone see my error?

OpenStudy (anonymous):

no

OpenStudy (kmeis002):

check the derivative of \(csc(t)\), plus be careful with your parenthesis.

OpenStudy (welshfella):

i cant remember the derivatives of cosec and cot...

OpenStudy (kmeis002):

and your addition signs, I'm not sure if you meant to put it there or if there's a typo.

OpenStudy (idku):

I would re-write in sines and cosines in the parenthesis combine and then differentiate using quotient,.

OpenStudy (anonymous):

deriv of csc(t) is -csc(t)*cot*(t) I don't think that part is incorrect. Are my parenthesis effecting my answer?

OpenStudy (welshfella):

derivative of cscc x = -cot x csc x and of cot x is - csc^2 x

OpenStudy (kmeis002):

You have it is \(-csc(t)+cot(t)\)

OpenStudy (welshfella):

* csc x

OpenStudy (welshfella):

yes the whole of the second part should be in parentheses

OpenStudy (anonymous):

Thank you so much! I suck at this stuff

OpenStudy (welshfella):

yw - it needs some practice to get confident in the more complicated derivatives

OpenStudy (anonymous):

Some calculations using Mathematica 9 are attached.

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