Question

If csc x = 7/3 and cot x = 2sqrt(10)/3, find sec x

Answer 1

HI there :)

Answer 2

Hi there again. Got up to another problem and got confused.

Answer 3

So.. one sec.

Answer 4

sin(\(\theta\)) = Opposite / Hypotenuse
cos(\(\theta\)) = Adjacent / Hypotenuse
tan(\(\theta\)) = Opposite / Adjacent

Answer 5

So I would need to find the reciprocal of csc and cot?

Answer 6

If think the answer is sec x = 7sqrt(10)/20

Answer 7

And

csc(\(\theta\)) = Hypotenuse / Opposite
sec(\(\theta\)) = Hypotenuse / Adjacent
cot(\(\theta\)) = Adjacent / Opposite

Answer 8

Sorry OS lagged and it took forever to post that -_-

Answer 9

So for csc x = 7/3 that means Hypotenuse is 7 and Opposite is 3.

Answer 10

If we solve for x, we get the adjacent side. And we already know the hypotenuse