Question

What is the angle of refraction of a light ray that enters the surface of a calm lake from air at an angle of 45o to the normal? The refractive index of water is 1.333.


32.04o

45.00o

59.99o

33.76o

Answer 1

You use snells law in this problem

\[n _{1} Sin \theta _{1} = n _{2}\sin \theta _{2}\]

Answer 2

refractive index of air should be ridiculously close to 1. So you would have
1 * sin(45) = 1.333 * sin(theta)

solve for theta