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Calculus1
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if h(x)=g(x)(f(x)+1), where f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7, find h'(2). this is what i have: h'(2)=g'(2)(f(2)+1)+(f(2)+1)'g(2) h'(2)=7(-3+1)+(-2)4 h'(2)=-22 is this right?
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