Question

can you help me solve each equation system by the addition method 4x+2y=6 4x-5y=-1.

Answer 1

anythingwill help lol

Answer 2

multiply 2nd equation by -1

Answer 3

substitute y=1 into the equation4x+2y=6
4x+2(1)=6
4x=6−2
4x=4
x=?

Answer 4

so x=1?

Answer 5

:) mhmm

Answer 6

would I do the same thing for y?

Answer 7

•/| 4*x+2*y-6 = 0| 4*x-(5*y)+1 = 0
•
•We try to solve the equation: 4*x+2*y-6 = 0
•4*x+2*y-6 = 0 // - 4*x-6
•2*y = -(4*x-6) // : 2
•y = (-(4*x-6))/2
•y = (6-(4*x))/2
•
•We insert the solution into one of the initial equations of our system of equations
•We get a system of equations:
•/| 4*x-(5*((6-(4*x))/2))+1 = 0| y = (6-(4*x))/2
•(-1*5*(6-4*x))/2+4*x+1 = 0
•14*x-15+1 = 0
•14*x-14 = 0
•
•14*x-14 = 0 // + 14
•14*x = 14 // : 14
•x = 14/14
•x = 1
•
•We insert the solution into one of the initial equations of our system of equations
•For y = (6-(4*x))/2:
•
•y = (6-(1*4))/2
•y = (6-4)/2
•y = 2/2
•y = 1
•
•We get a system of equations:
•/| y = 1|
x = 1

Answer 8

so ur y and x are both equal to 1 :)

Answer 9

I get it now!! Thank you :)

Answer 10

Your Welcome :)

Answer 11

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