Question

hey need some help with sqrt in fortran

Answer 1

i was doing z=sqrt(x.x+1)
the equation I'm solving is \[y=\sqrt{x^2+1}\]

Answer 2

i mean z not y

Answer 3

@Abhisar

Answer 4

@ganeshie8 any fortran experience ^_^

Answer 5

From https://www.nsc.liu.se/~boein/f77to90/a5.html

The purpose of most of these functions is obvious. Note that they are all only defined for floating point numbers, and not for integers. You can therefore not calculate the square root of 4 as SQRT(4), but instead you can use NINT(SQRT(REAL(4))). Please also note that all complex functions return the principal value.

Answer 6

when specify the equation the compiler doesn't understand SQRT()