if x^2+x+y=8 and x0,then what is the value of y-8/x(x+1)?

Question

if x^2+x+y=8 and x>0,then what is the value of y-8/x(x+1)?

ganeshie8 · Answer

Hint : 
$$x^2+x = x(x+1)$$

anonymous · Answer

i did not get it?

ganeshie8 · Answer

$$x^2+x+y=8$$

$$y-8 = -(x^2+x)$$

divide both sides by $x^2+x$

kittiwitti1 · Answer

Do you still need help @arisonal ?

anonymous · Answer

thank you so much i got the answer:)

kittiwitti1 · Answer

... ?

anonymous · Answer

if x/3y=4/7 and z/5y=2/21,then x/z=                                                                                A) 5/18                                                                                                                           B)  18/5                                                                                                                      C) 7/36                                                                                                                     D)none of these

anonymous · Answer

-1