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The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance can the cross section be a non-rectangular parallelogram? When the plane cuts three faces of the cube, separating one corner from the others When the plane passes through a pair of vertices that do not share a common face When the plane is perpendicular to the base and intersects two adjacent vertical faces When the plane makes an acute angle to the base and intersects three vertical faces Not enough information to answer the question
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