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Short = 5 , hypotenuse = 10 Long =
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\[(short)^2+(long)^2=(hypotenuse)^2\]
Have you read about right triangles?
yes
|dw:1424280084458:dw|
yes been there but havent seen the problem lay out before
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brb
\[short=a\] \[long=b\] \[hyp=c\]\[a^2+b^2=c^2\]\[b^2=c^2-a^2\] can you find the b(long) now?
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