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OpenStudy (gabylovesyou):
Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution. x = 6, solution is not extraneous x = 6, solution is extraneous x = 11, solution is not extraneous x = 11, solution is extraneous the answer is A ?
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OpenStudy (gabylovesyou):
@SolomonZelman
OpenStudy (anonymous):
A
Nnesha (nnesha):
yes right goood job :)
Nnesha (nnesha):
|dw:1424289836603:dw| both side equal perfect!
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