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why would you not leave it as a 4th root of i though... I would, but that is just me.
\[\frac{1}{i^4}=\frac{1}{(i^2)^2=}\\=\frac{1}{(-1)^2}=1\]
None of those are answer choices.
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nevermind, the wolfralpha did give me cos(pi/8) + i sin(pi/8), which I can convert to standard form, which is answer choice b.
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