Question

Hey You guys! Could you please help me with this? I need a walk-through please.
(I will draw the triangle)
Find the value of x. Round to the nearest tenth. The diagram is not drawn to scale.

Answer 1

SOH CAH TOA
sin(x) = opposite/hypotenuse
cos(x) = adjacent/hypotenuse
sin(x) = opposite/adjacent

x = angle

Rules for solving for x
arcsin(sin(x)) = x
arccos(cos(x)) = x
arctan(tan(x)) = x

http://en.wikipedia.org/wiki/Trigonometry
look at diagram of triangle and read caption

Answer 2

adjacent and opposites location is dependent on the angle you use in the triangle

Answer 3

i have to go, so could you please try and hurry?

Answer 4

for example:

Answer 5

If we had angle A = 30 degrees
b = 10degrees and we wanted to solve for a

notice


so,

SOH CAH TOA

we have adjacent and we are solving for opposite so use tan(x)

tan(x) = OPPOSITE

Answer 6

@Australopithecus

Answer 7

wow I just lost all my work.

Answer 8

Ok so imagine we have angle A = 30 degrees
b = 20
and we want to solve for a

notice since we have angle A we use:


we want to solve hyp and we have adj so remember

SOH CAH TOA

we use
cos(x) = adjacent/hypotenuse
cos(A) = b/a
so,

cos(30) = 20/a

cos(30)a = 20
a = cos(30)/20

plug into your calculator (make sure it is set to deg and not rad) and you will have an answer