Question

Three vertices of square ABCD are A(–1, –5), B(–3, –1), and C(1, 1).

What are the coordinates of the fourth vertex?

Answer 1

with 3 points you can make the equation of two lines: the line AB and the line BC

Answer 2

the line CD is parallel to the line BA and the line BC is parallel to the line AD

Answer 3

the equation of a line can be done in two forms the 'slope intercept' and the 'point slope'

Answer 4

@AlexandervonHumboldt2

Answer 5

0,3

Answer 6

9

Answer 7

@AlexandervonHumboldt2

Answer 8

@TheEdwardsFamily

Answer 9

I do not know this! srry :(

Answer 10

its okay can you help me tag ppl?

Answer 11

sure

Answer 12

@mathmath333 @Godlovesme @Destinymasha

Answer 13

@pooja195

Answer 14

@Directrix @Godlovesme

Answer 15

sorry idk :(

Answer 16

:( itso kay help us tag?

Answer 17

@pooja195

Answer 18

@freckles @Hero @gigi2002 @grrrxxiii

Answer 19

Its only 7 of my fans that r online

Answer 20

now 9

Answer 21

@Luigi0210 same here

Answer 22

@haleyelizabeth2017 @dtan5457 @jordanloveangel

Answer 23

I don't remember :/ sorry!

Answer 24

@HaileyD help leae

Answer 25

and at the same time im trying to help other peole! sheez, how many places can i be at once? :/

Answer 26

HELP

Answer 27

WUT THE Questions

Answer 28

Three vertices of square ABCD are A(–1, –5), B(–3, –1), and C(1, 1).

What are the coordinates of the fourth vertex?

Answer 29

-4 ,5?

Answer 30

4<5

Answer 31

srry not good at this

Answer 32

the idea here is to find the equation of line dc which will have slope same as
line ab.

and find the equation of line ad which will have the same slope as line bc

then u have to solve the two equations for (x,y)

Answer 33

its okay cake

Answer 34

@ilovewolf i dont understand tho

Answer 35

help PLESASE DX

Answer 36

do you have a screenshot of the question?
Maybe that could help me understand better >.>

Answer 37

http://prntscr.com/66x4wp

Answer 38

\(\large \begin{align} \color{black}{
y-1=\dfrac{(5-(-1))}{(-1-(-3))}(x-1)----------1 \hspace{.33em}\\~\\
y-5=\dfrac{(1-(-1))}{(1-(-3))}(x-(-1))----------2 \hspace{.33em}\\~\\
}\end{align}\)

solve the 2 equations

Answer 39

O.O CAN YOU EXPLAN THAT PLEASE

Answer 40

@~Samson245~