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Trigonometry
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Find the area of the shaded region in the figure. (Round your answer to one decimal place.) b=13 angle pi/3
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5/6 times the area of the circle plus the area of the equilateral triangle. \[\frac{5 \pi 13^2}{6}+\frac{\sqrt{3} 13^2}{4}=\frac{169}{12} \left(3 \sqrt{3}+10 \pi \right)=515.6 \]
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