Question

csc^2 x/sec^2 x

Answer 1

Hints:
\(\csc x = \dfrac{1}{\sin x}\)
\(\sec x = \dfrac{1}{\cos x}\)
\(\tan x = \dfrac{\sin x}{\cos x}\)
Substitute and work out the fraction.

Answer 2

or multiply times cos^2x on top and bottom, and multiply times sin^2x on top and bottom.

Answer 3

@SolomonZelman So if I do that would I get cos^2xsinx/sin^2xcosx?