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Algebra
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solve, x^2-4xy+4y^2
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\[x^2-4xy+4y^2\]Split the middle term in half.\[x^2-2xy-2xy+4y^2\]
Now group each of the two terms together, and from those two groups, pullout like terms. \[(x^2-2xy)+(-2xy+4y^2)\]
\[(\color{red}{x}^2 - 2\color{red}{x}y)+(\color{red}{-2y}x+\color{red}{4y}^2)\]
\[x^2-4 x y+4 y^2=(x-2 y)^2 \]
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