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is X^1/5 and X^2/5 odd, even, or neither?
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how?
you have to replace x by -x and then solve if you get same result like original question then its its even
if f(x) = f(-x) the function even, else if -f(x) = f(-x) it is odd, else it is either
yes but i cant use a calc so wht does the exponent 2/5 lets say do when you input -X?
isn't it \[ \huge\rm \frac{ x^2 }{ 5 }\]????
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let x=1 and let x=-1
i assumed it was x^(2/5)
haha oops sorry ! but yeah i think i got it now thanks !
so that was x^2 divided by 5 ?
no, exponent
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okay \(\rm\color{green}{o^\wedge\_^\wedge o}\)
but thanks !
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