Question

The root 6 has a factor of (x-6), the root -2 has a factor of (x-(-2)), and the root -7 has a factor of (x-(-7)). Multiplying (x-6) and (x+2), I get x^2-4x-12. Then I multiply this by (x+7), so (x^2-4x-12)(x+7). This results in a function of f(x)=x^3 + x^2-28x-12x-84