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For the polynomial … - QuestionCove
OpenStudy (howard-wolowitz):

For the polynomial function ........................... find all local and global extrema.

2 years ago
OpenStudy (howard-wolowitz):

A. No local extrema exist.

2 years ago
OpenStudy (howard-wolowitz):

B. the only extrema point is (9,0).

2 years ago
OpenStudy (howard-wolowitz):

C. The only extrema point is (-1.62, 0)

2 years ago
OpenStudy (howard-wolowitz):

D. The local and global extrema are: (-3,0) , (0,-1.62) and (3,0)

2 years ago
OpenStudy (howard-wolowitz):

Also guys Im not sure what the answer is

2 years ago
OpenStudy (anonymous):

It's asking you to look for a max/min, it's best if you graph it out

2 years ago
OpenStudy (howard-wolowitz):

ok, but how would you graph that out

2 years ago
OpenStudy (anonymous):

Computer :P

2 years ago
OpenStudy (howard-wolowitz):

I worked it earlier with my brother and he said it was B!

2 years ago
OpenStudy (anonymous):

Is that suppose to be a x or x^2 -> 0.36x^2?

2 years ago
OpenStudy (howard-wolowitz):

x^2

2 years ago
OpenStudy (anonymous):

Ok, then it's just a parabola

2 years ago
OpenStudy (howard-wolowitz):

oh crap sorry

2 years ago
OpenStudy (howard-wolowitz):

let me redo it one sec sorry

2 years ago
OpenStudy (howard-wolowitz):

\[f(x)= -0.02x ^{4} + .36x ^{2} - 1.62\]

2 years ago
OpenStudy (howard-wolowitz):

Ok so the line is touching it a three spots so it has to be D right?

2 years ago
OpenStudy (anonymous):

Use this: https://www.desmos.com/calculator

2 years ago
OpenStudy (howard-wolowitz):

what do i type in for it?

2 years ago
OpenStudy (anonymous):

Put in your function

2 years ago
OpenStudy (howard-wolowitz):

ok

2 years ago
OpenStudy (howard-wolowitz):

stupid expoent doesnt work

2 years ago
OpenStudy (anonymous):

The graph I gave you was wrong, because I put -0.002 not -.02, and for exponents use this "^"

2 years ago
OpenStudy (howard-wolowitz):

never i see how to use it

2 years ago
OpenStudy (anonymous):

|dw:1424352878146:dw| so this is how it is

2 years ago
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