Question

Make and run a program that will display the numbers 1, 2, 3, and so on depending on the number of lines the user will enter. For example, if input=3, first line of output should be 1, next line 2 3, and the last line 4 5 6 using a do-while loop. I'm using c++, I can't solve this problem. Can you please help me out? ASAP

Answer 1

I don't know c++ but I can give you program in c.

#include<stdio.h>
#include<conio.h>
void main()

int i=1, n;
scanf ("%d", &n);
if (i<=n)
printf("%d /n", &n);
i++;
else
getch();

if you are learning c++ then this means that you already know c language.
you just need to convert the above code into c++ syntax.

NOTE: THE ABOVE CODE WILL GIVE YOU A BASIC IDEA OF WHAT HAS TO BE DONE. SOMETHING LIKE AN ALGORITHM.

Answer 2

anuragbansal, never assume that "if you are learning c++ then this means that you already know c language. you just need to convert the above code into c++ syntax."

Many people are taught C++ without learning C. In fact, C is now being taught later and later, if at all, because it has returned to more of an operating system development language while other languages have become more general purpose.

Answer 3

mguy1, can you describe to me how you would solve this problem in English (or some other more familiar computer programming language). Once you got a handle on how to solve this problem, you can work on converting it to C++.

Answer 4

do
{
int i = 0;
// read a line of input
cout << ++i << input << endl;
}
while( !feof );

Answer 5

Hello, mguy1. I'm a beginner in C programming. I dnt knw if you have succeded. But, i coded in C (code::blocks) and i got the program working.

Answer 6

here's the code:
#include <stdio.h>

void main()
{
int i,j,n;

printf("Enter the degree: ");
scanf("%d",&n);

int t[n][n];

for(i=0;i<n;i++)
{
t[0][0]=0;
t[i][0]=t[i-1][i-1] + 1;

for(j=1;j<=i;j++)
{
t[i][j]=(t[i][j-1]) + 1;
}
}

for(i=0;i<n;i++)
{
for(j=0;j<=i;j++)
{
printf("%5d",t[i][j]);
}
printf("\n");
}
}