Question

Which are real zeroes of this function?
x3 + 2x2 – 9x – 18

Answer 1

hint : try to factor \(x^2\) out

Answer 2

@satellite73

Answer 3

\(\large \begin{align} \color{black}{hint:\\~\\x^3 + 2x^2 – 9x – 18 \hspace{.33em}\\~\\
=x^2(x + 2)– 9(x + 2) \hspace{.33em}\\~\\
}\end{align}\)

Answer 4

What do I do with that hint?

Answer 5

good question

Answer 6

\(\large \begin{align} \color{black}{x^3 + 2x^2 – 9x – 18 \hspace{.33em}\\~\\
=x^2(x + 2)– 9(x + 2) \hspace{.33em}\\~\\
=(x^2-9)(x + 2) \hspace{.33em}\\~\\
=(x^2-3^2)(x + 2) \hspace{.33em}\\~\\
=(x-3)(x+3)(x + 2) \hspace{.33em}\\~\\
}\end{align}\)

Answer 7

still need help

Answer 8

x=-3,3,2 are the zeroes

Answer 9

THank you. So the ral zero's of the function are 3, -3, 2.

Answer 10

real*

Answer 11

\(\large \begin{align} \color{black}{(x-3)(x+3)(x + 2) =0 \hspace{.33em}\\~\\
}\end{align}\)

find 3 x values u will get the same.

Answer 12

THank you Grandmaster.