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A series circuit contains a 9-volt battery, a 3-ohm resistor and a 2-ohm resistor. What is the voltage drop across the 2-ohm resistor? 3.4 V 3.6 V 3.8 V
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@dtan5457
Gotta use the ohm law. V=IR v=voltage I=current R=resistance They tell you the voltage is 9 and that the resistance is 2 and 3. You first have to calculate the current. 9=I(5) To get I, you must do 9/5 which is 1.8 amps Now..to get your voltage drop for 2 ohm resistor.. Just do 1.8 x 2..
thnx
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