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solve sinx+1=cosx
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sin - cos =-1 square both sides -2sin cos =0 sin =0 or cos =0 you do the rest, ok?
@Jackie.torres87 can you solve therest?
The only step @Loser66 skipped over, that you may want to reference, is:\[(\sin(x)-\cos(x))^2 = \color{red}{\sin^2(x)} -2\sin(x)\cos(x)\color{red}{+\cos^2(x)} = -2\sin(x)\cos(x)\color{red}{+1}\]
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