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A central pivot irrigation system is watering a circular field with a radius of 120 feet. The system rotates pi/6 radians in one hour. What area ( to the nearest square foot) is watered in one hour?
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area of a semi -circle is pi*r^2 / 2. so first the total area is .5* pi*120^2 take this value and divide by a 6th to get the area covered by the system.
so your final equation is: 120^2*pi / 12 .
ok thanks
wait so thats my answer?
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