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log_{sqrt 2}(x + 1) = 2
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\[\log_{\sqrt 2}(x + 1) = 2\]
Where 2 is log 100 i guess.
x+1 = sqrt2 ^2
x+1= 2 x=1
property of logarithms
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Property of Logs: \[\log_a (b) = c \implies a^c = b\] Use it to solve for \(x\)..
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