Question

Use the figure to find all angles between 0 and 2\pi satisfying the given condition \sin \theta=\frac{\sqrt{2}}{2}.

Answer 1

is this your Q
\[\rm solve~ \sin \theta=\frac{\sqrt{2}}{2},~~~~~for ~~\theta \in [0,2\pi]\]

Answer 2

if so what angle do you think gives \[\sqrt{2}/2\] if you take sin of it

Answer 3

yea
between (0,2pi)

Answer 4

hmm i will give you one and you do the other
\[\sin (\pi/4)=\sqrt{2}/2\]

Answer 5

but i don't get how to even solve it