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ok so solve for cos... because of the domain, \[2 \cos(\theta) = 1~~so~~~\cos(\theta) = \frac{1}{2}\] find the angle you need the 1st quadrant and 4th quadrants 1st quadrant its \[1st ~quarant = \theta~~~~~4th ~quadrant~ = (360 - \theta)\]
do you have a detailed link that explains this stuff? i don't think i even learned this yet..
have a look at these online notes http://tutorial.math.lamar.edu/ they are well written with plenty of examples... sorry I didn't get the specific trig stuff... but its in there
oh yeah, i see them. i'll look at them right now, thanks.
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