Question

In this problem verify that the given functions y1 and y2 satisfy the corresponding homogenous equation. Then find a particular solution of the non homogenous equation x^2y'' -3xy'+4y=19x^2ln(x). y1=x^2 and y2=x^2ln(x).

Answer 1

I used the method of parameters and I keep getting (-19/4)x^4ln(x) + (19/4)x^4 for the particular solution but the answer is wrong.

Answer 2

method of variation of parameters*