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Show that the curve y=10x^3+4x+2 has no tangent lines with slope 3.
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HI!!
take the derivative, you will get a quadratic
set it equal to 3 and try to solve no doubt you will get no solution, i.e. a discriminant that is negative
how do you take a derivative? @misty1212
i got 0=30x^2+1
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Derivative should be 30x^2+4 (because your x has a coefficient of 4)
oh i set it to equal to 3
do you not know how to find the derivative of a polynomial?
i think so, it will be y'= 30x^2+4
\[30x^2+4=3\\ 30x^2=-1\] no real solution
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oh i see thanks!
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